K(x)=5x^2+12

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Solution for K(x)=5x^2+12 equation: 



(K)=5K^2+12

We move all terms to the left:

(K)-(5K^2+12)=0

We get rid of parentheses

-5K^2+K-12=0

a = -5; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·(-5)·(-12)
Δ = -239
Delta is less than zero, so there is no solution for the equation

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